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  1. summation - Prove that $1^3 + 2^3 + ... + n^3 = (1+ 2

    HINT: You want that last expression to turn out to be $\big (1+2+\ldots+k+ (k+1)\big)^2$, so you want $ (k+1)^3$ to be equal to the difference $$\big (1+2+\ldots+k+ (k+1)\big)^2- …

  2. Proving $1^3+ 2^3 + \cdots + n^3 = \left (\frac {n (n+1)} …

    Dec 9, 2014 · Hint $ $ First trivially inductively prove the Fundamental Theorem of Difference Calculus $$\rm\ F (n) = \sum_ {k\, =\, 1}^n f (k)\, \iff\, F (n) - F (n\!-\!1)\, =\, f (n),\ \ \, F (0) = …

  3. Big-O Notation - Prove that $n^2 - Mathematics Stack Exchange

    Jul 5, 2013 · Would this book be Kenneth H. Rosen's "Discrete Mathematics and its Applications" by any chance? If so, I found all of the material easily digestible until this section, where I feel …

  4. how to prove that $f (n)=n^3+n\log^2n$ = $\theta (n^3)$?

    Nov 21, 2018 · i didn't really understand the hint .. is this a way toprove that nlog2n/n3 <= 1 ?

  5. Use mathematical induction to prove that $n^ 3 − n$ is divisible …

    Solution: Let $P(n)$ be the proposition “$n^3−n$ is divisible by $3$ whenever $n$ is a positive integer”. Basis Step:The statement $P(1)$ is true because $1^3 ...

  6. Proof that $n^3+2n$ is divisible by $3$ - Mathematics Stack …

    Let n^3+2n = P (n). We know that P (0) is divisible by 3. The inductive step shows that P (n+1) = P (n) + (something divisible by 3). So if P (0) is divisible by 3, then P (1) is divisible by 3, and …

  7. Series convergence test, $\sum_ {n=1}^ {\infty} \frac { (x-2)^n} …

    Jun 28, 2020 · By the ratio test, every x value between -1 and 5 would make the series converge. we just need to find out whether x=-1, 5 makes it converge. x=-1: The series will look like this. …

  8. algorithms - How to arrange functions in increasing order of …

    Given the following functions i need to arrange them in increasing order of growth a) $2^ {2^n}$ b) $2^ {n^2}$ c) $n^2 \log n$ d) $n$ e) $n^ {2^n}$ My first attempt ...

  9. How to prove that $6n^2 + 20n \notin \Omega { (n^3)}$

    Sep 1, 2016 · I'm not sure how to go about this, I've tried finding constants and N values to find out, for instance I tried to prove it through contradiction but I must be doing something wrong …

  10. Existence of normal subgroups for a group of order $36$

    Oct 30, 2012 · Let n3 be the number of 3-Sylow subgroups of G. then n3=1 or n3=4 if n3=1 we have 1 3-sylow group of order 9. and it is also a normal group (from sylow theorem ) if n2=1 …